Question

Two adjacent angle of a rhombus are (3x-4)⁰ and (3x+16)⁰ respectively. Find the measure of each angle ?​

Answer 1

Step-by-step explanation:

SOLUTION: TWO ADJACENT ANGLES OF A PARALLELOGRAM ARE (3X-4) AND (3X+16) FIND THE VALUE OF X AND HENCE FIND THE MEASURE OF EACH OF ITS ANGLES. The two adjacent angles of a parallelogram = 180 degrees. (3x + 16) = 100 degre

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Answer 2

$\bf{\underline{Question:-}}$

Two adjacent angle of a rhombus are (3x-4)⁰ and (3x+16)⁰ respectively. Find the measure of each angle.

$\bf{\underline{Given:-}}$

• Two adjacent angle of a rhombus are (3x-4)⁰ and (3x+16)⁰

$\bf{\underline{Note:-}}$

• The sum of two adjacent angle of parallelogram is 180° or they are supplementary.

$\bf{\underline{Solution:-}}$

$\sf → ( 3x - 4) + (3x+16)=180$

$\sf → 3x - 4 + 3x + 16 = 180$

$\sf → 6x +12 = 180$

$\sf → 6x = 180-12$

$\sf → 6x = 168$

$\sf → x = 168/6$

$\sf → x = 28$

$\bf{\underline{Hence:-}}$

• First adjacent angle 3x - 4

⏩ 3 × 28 - 4

⏩ 84 - 4

⏩ 80 ° 【 First angle 】

• Second adjacent angle 3x + 16

⏩ 3 × 28 + 16

⏩ 84 + 16

⏩ 100° 【 second angle 】