Question

two adjacent angles of a parallelogram are 3 x minus 4 degree and 3 X + 16 degree find the value of x and hence find the measure of each of its angles

Answer 1

Given equation is (3x - 4)(3x + 16).

We know that Sum of adjacent angles of a parallelogram is 180.

Therefore (3x - 4) + (3x + 16) = 180

                  3x - 4 + 3x + 16 = 180

                   6x + 12 = 180

                      6x = 168

                        x = 168/6

                        x = 28 degrees.

x = 28 degrees.

3x - 4 = 3 * 28 - 4 

          = 84 - 4

          = 80 degrees.

3x + 16 = 3 * 28 + 16

            = 84 + 16

            = 100 degrees.

The measure of each of its angles is 28, 80 and 100.

Hope this helps!

Answer 2

as we know that the sum of the adjacent angles of a parallelogram is equal to 180 degree so that angle A is equal to 3 x minus 4 degree and Angle b is equal to 3 X + 16 degree
then,
angle A + angle b =180
3x -4 +3x+16 = 180
6x + 12 =180
6x = 180 - 12
6x = 168
x = 168/6
x = 28
so, angle a = 3x - 4
= 3(28) - 4
= 84-4 = 80
angle b = 3x +16
= 3(28) + 16
= 84 +16 = 100

angle c =angle a = 80
angle d = angle b =100