Two adjacent angles of a parallelogram are (3x + 20)° and (2x + 10)° , then find the
value of ‘x’ .
Answers
GivEn:
- Adjacent angles = (3x + 20)° and (2x + 10)°.
To find:
- The value of x.
Solution:
• In a parallelogram sum of adjacent angles is equal to 180 degrees.
Here, Adjacent angles are,
- (3x + 20)°
- (2x + 10)°
⠀⠀━━━━━━━━━━━━━━━━━━━⠀
« Now, Finding the value of x,
As we know that,
- Sum of adjacent angles will add up to 180 degrees.
→ (3x + 20)° + (2x + 10)° = 180°
→ 5x + 30° = 180°
→ 5x = 180° - 30°
→ 5x = 150°
→ x = 150/5
→ x = 30°
Therefore,
- (3x + 20)° = 3(30) + 20° = 90 + 20 = 110°
- (2x + 10)° = 2(30) + 10° = 60 + 10 = 70°
∴ Hence, The value of x is 30° & Adjacent angles are 110° & 70°.
Answer:
GivEn:
Adjacent angles = (3x + 20)° and (2x + 10)°.
To find:
The value of x.
Solution:
• In a parallelogram sum of adjacent angles is equal to 180 degrees.
Here, Adjacent angles are,
(3x + 20)°
(2x + 10)°
⠀⠀━━━━━━━━━━━━━━━━━━━⠀
« Now, Finding the value of x,
As we know that,
Sum of adjacent angles will add up to 180 degrees.
→ (3x + 20)° + (2x + 10)° = 180°
→ 5x + 30° = 180°
→ 5x = 180° - 30°
→ 5x = 150°
→ x = 150/5
→ x = 30°
∴ Hence, The value of x is 30° & Adjacent angles are 110° & 70°.