Question

Two adjacent angles of a parallelogram are (3x-4)° and (3x+10)°, then find angles of the parallelogram. *

Answer 1

EXPLANATION.

=> Two adjacent angles of a parallelogram

=> ( 3x - 4 )° and ( 3x + 10 )°

To find angle of the parallelogram.

As we know that,

The adjacent sides of a parallelogram are equal.

=> ( 3x - 4 )° + ( 3x + 10 )° = 180

=> 3x - 4 + 3x + 10 = 180

=> 6x + 6 = 180

=> 6x = 174

=> x = 174 / 6

=> x = 29°

Therefore,

=> ( 3x - 4 )° = ( 3 X 29 - 4 )° = 83°

=> ( 3x + 10 )° = ( 3 X 29 + 10 ) = 97°

Measure of each angle is.

=> 83° , 97° , 83° , 97°

Answer 2

$\bf \huge { \underline{ \underline{ \red{Question:}}}}$

Two adjacent angles of a parallelogram are (3x-4)° and (3x+10)°, then find angles of the parallelogram.

$\bf \huge { \underline{ \underline{ \red{Answer:}}}}$

$\bf { \purple{ \underline{Given:-}}}$

• Two adjacent angles of a parallelogram are (3x-4)° and (3x+10)°

$\bf { \purple{ \underline{To \: \: Find:-}}}$

• angles of the parallelogram.

$\bf{ \purple{ \underline{Soln :-}}}$

In parallelogram , sum of adjecent angles is 180°

$\therefore \sf \: (3x - 4) \degree + (3x + 10) \degree = 180 \degree \\ \\ \large \implies \sf \: 3x - 4 + 3x + 10 = 180 \\ \\ \large \implies \sf \:6x + 6 = 180 \\ \\ \large \implies \sf \:6x = 180 - 6 \\ \\ \large \implies \sf \:6x = 174 \\ \\ \large \implies \sf \:x = \frac{174}{6} \\ \\ \large \implies \sf \:x = 29 \degree \\ \\ \sf \: (3x - 4) \degree = (3 \times 29 - 4) = 83 \degree \\ \\ \sf \: (3x + 10) \degree = (3 \times 29 + 10) = 97 \degree$

we know that,

In parallelogram opposite angles are equal

•°• Four angles of parallelogram is 83° , 97° , 83° and 97°