Question

Two adjacent angles of a parallelogram are (3x − 4)° and (3x + 16)°. Find the value of x and hence find the measure of each of its angles.


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Answer 1

Answer:

Let ∠A = (3x-4)o and ∠B = (3x+16)o Let ∠A and ∠B are two adjacent angles. But we know that sum of adjacent angles of a parallelogram is 180o ∠A + ∠B = 180o (3x-4)o + (3x+16)o= 180o 6x + 12 = 180o 6x = 180o-12o 6x = 168o X= 168o/6 = 280 ∠A = (3x-4)o=3 × 28 – 4 = 80o ∠B = (3x+16)o= 3 × 28 + 16 = 100o Also ∠B + ∠C = 180o [Since ∠B and ∠C are adjacent angles] 100o+ ∠C = 180o ∠C = 180o– 100o= 80o. Now ∠C + ∠D = 180o [Since ∠C and ∠D are adjacent angles] 80o+ ∠D = 180o ∠D = 180o– 80o= 100oRead more on Sarthaks.com - https://www.sarthaks.com/738559/adjacent-angles-parallelogram-and-find-value-and-hence-find-the-measure-each-its-angle

Answer 2

Answer:

refer to the attachment..

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