Question

Two adjacent angles of a parallelogram are (3x-4) and (3x+16). Find the measure of each of its angle

Answer 1

Answer:

3x-4+3x+16=180

6x+12=180

180-12=168=6x

x=168/6=28

3x-4=84-4=80

3x+16=84+16=100

Hence, the angles are 100 and 80

Answer 2

$\large\underline\pink{Given:-}$

• The adjacent angle of a parallelograms are (3x - 4) and (3x + 16).

$\large\underline\pink{To find:-}$

• Fine the value of x. measure of each of its angle ....?

$\large\underline\pink{Solutions:-}$

Sum of any adjacent angle of a parallelogram = 180°

⟹ (3x - 4) + (3x + 16) = 180°

⟹ 3x - 4 + 3x + 16 = 180

⟹ 6x + 12 = 180

⟹ 6x = 180 - 12

⟹ 6x = 168

⟹ x = 168/6

⟹ x = 28cm

The value of x is 28cm.

(3x - 4)

⟹ 3 × 28 - 4

⟹ 84 - 4

⟹ 80cm

(3x + 16)

⟹ 3 × 28 + 16

⟹ 84 + 16

⟹ 100 cm

Hence, the measure of each of its angle is 80cm and 100cm.

$\large\underline\pink{More \: \: Information:-}$

Area of parallelogram = base × height perimeter = 2 (l + b)

where,

• l = length
• b = breadth
• a = area
• p = perimeter