Two adjacent angles of a parallelogram are (3y − 20)˚ and (3y + 80 )˚.
Find the value of y and hence find the measure of each of its angles.
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Solution:-
Let us consider a parallelogram ABCD with ∠DAB = (3y - 20)° and ∠ABC = (3y + 80)°.
Now,
We know,
- Sum of the adjacent angles of a parallelogram is 180°.
Therefore,
So,
- ∠DAB = (3y - 20)° = (3×20 - 20)° = 40°
and
- ∠ABC = (3y + 80)° = (3×20 + 80)° = 140°
Now,
We know
Opposite angles of a parallelogram are equal.
Therefore,
- ∠DCB = ∠DAB = 40°
and
- ∠ADC = ∠ABC = 140°.
Explore more :-
- A parallelogram is a quadrilateral with two pairs of parallel sides.
- The opposite sides of a parallelogram are equal in length, and the opposite angles are equal in measure.
- Also, the interior angles on the same side of the transversal are supplementary.
- Sum of all the interior angles equals 360 degrees.
- Rhombus: If all the sides of a parallelogram are congruent or equal to each other, then it is a rhombus.
- If there is one parallel side and the other two sides are non-parallel, then it is a trapezium.
If ABCD is a parallelogram, where AB || CD and AD || BC.
- Also, AB = CD and AD = BC
- And, ∠A = ∠C & ∠B = ∠D
Also, ∠A & ∠D are supplementary angles because these interior angles lie on the same side of the transversal.
In the same way, ∠B & ∠C are supplementary angles.
Therefore,
- ∠A + ∠D = 180
- ∠B + ∠C = 180
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