Question

Two adjacent angles of a parallelogram are in the ratio 4: 5. Find the measure of each of its angles.​

Answer 1

Sum of the adjacent angles in any parallelogram= 180

Sum of the adjacent angles in any parallelogram= 180ratio of adjacent angles = 4:5 (given)

um of the adjacent angles in any parallelogram= 180ratio of adjacent angles = 4:5 (given)let first angle = 4x

um of the adjacent angles in any parallelogram= 180ratio of adjacent angles = 4:5 (given)let first angle = 4xsecond angle = 5x

um of the adjacent angles in any parallelogram= 180ratio of adjacent angles = 4:5 (given)let first angle = 4xsecond angle = 5x4x+5x=180

um of the adjacent angles in any parallelogram= 180ratio of adjacent angles = 4:5 (given)let first angle = 4xsecond angle = 5x4x+5x=1809x=180

um of the adjacent angles in any parallelogram= 180ratio of adjacent angles = 4:5 (given)let first angle = 4xsecond angle = 5x4x+5x=1809x=180x=180/9

um of the adjacent angles in any parallelogram= 180ratio of adjacent angles = 4:5 (given)let first angle = 4xsecond angle = 5x4x+5x=1809x=180x=180/9x= 20

um of the adjacent angles in any parallelogram= 180ratio of adjacent angles = 4:5 (given)let first angle = 4xsecond angle = 5x4x+5x=1809x=180x=180/9x= 20therefore

um of the adjacent angles in any parallelogram= 180ratio of adjacent angles = 4:5 (given)let first angle = 4xsecond angle = 5x4x+5x=1809x=180x=180/9x= 20thereforerequired angles are

um of the adjacent angles in any parallelogram= 180ratio of adjacent angles = 4:5 (given)let first angle = 4xsecond angle = 5x4x+5x=1809x=180x=180/9x= 20thereforerequired angles arefirst angle = 4x= 4*20 =80

um of the adjacent angles in any parallelogram= 180ratio of adjacent angles = 4:5 (given)let first angle = 4xsecond angle = 5x4x+5x=1809x=180x=180/9x= 20thereforerequired angles arefirst angle = 4x= 4*20 =80second angle = 5x= 5*20 =100

Answer 2

Answer:

There it is with explanation