Question

Two adjacent angles of a parallelogram are in the ratio of 3 is to 8 and its perimeter is 110 CM find the sides of the parallelogram

Answer 1

let the common faxtor be x
therefore,
length and breadth= 3x and 8x
2(8x+3x)=110
2×11x=110
x=5

3x=3×5=15
8x=8×5=40

Answer 2

Adjacent Sides = 15 & 40 cm ✬

Step-by-step explanation:

Given:

Two adjacent sides of a parallelogram are in ratio 3 : 8.

Perimeter of parallelogram is 110 cm.

To Find:

What is the meaure of sides of ||gm ?

Solution: Let x be the common in given ratio. Therefore,

➨ Length of ||gm = 3x

➨ Breadth of ||gm = 8x

As we know that, Opposite sides of a parallelogram are equal so other two adjacent sides will be same.

★ Perimeter of ||gm = Sum of its all sides ★

\implies{\rm }⟹ 110 = 3x + 3x + 8x + 8x

\implies{\rm }⟹ 110 = 6x + 16x

\implies{\rm }⟹ 110 = 22x

\implies{\rm }⟹ 110/22 = x

\implies{\rm }⟹ 5 = x

So,

➫ Length = 3x = 3(5) = 15 cm.

➫ Breadth = 8x = 8(5) = 40 cm.

Hence, two adjacent sides of the parallelogram are 15 cm & 40 cm.