two adjacent angles of a parellelogram are (3x-4)and (3x+16) find the value of x and hence find the measure of each of its angles
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sum of two adjacent angles = 180
[by theorem]
3x-4 + 3x+16 = 180
6x =168
x = 28
Therefore, all the angles are----
80°,100°,80°,100°
[by theorem]
3x-4 + 3x+16 = 180
6x =168
x = 28
Therefore, all the angles are----
80°,100°,80°,100°
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