Two adjacent angles of a parellogram are in the ratio 4:5 find the measure of each of its angle
Answers
Answered by
7
Heya ✋
Let see your answer !!!
Let ABCD be the given parallelogram in which two adjacent angles of a parallelogram be 4x and 5x.
< A = < C [opposite angles of parallelogram are equal]
< B = <D [opposite angles of parallelogram are equal]
4x + 5x + 4x + 5x = 360
=> 18x = 360
=> x = 360/18
=> x = 20
Hence , < A = < C = 4 × 20 = 80°
< B = < D = 5 × 20 = 100°
Hence , the angles of the parallelogram are 80° , 100° , 80° and 100°.
Thanks :)))
Let see your answer !!!
Let ABCD be the given parallelogram in which two adjacent angles of a parallelogram be 4x and 5x.
< A = < C [opposite angles of parallelogram are equal]
< B = <D [opposite angles of parallelogram are equal]
4x + 5x + 4x + 5x = 360
=> 18x = 360
=> x = 360/18
=> x = 20
Hence , < A = < C = 4 × 20 = 80°
< B = < D = 5 × 20 = 100°
Hence , the angles of the parallelogram are 80° , 100° , 80° and 100°.
Thanks :)))
Answered by
4
Let,
Angles are,
4x, 5x, 4x, 5x
Now,
4x+5x+4x+5x = 360
18x =360
x=360/18
x =20
Now,
Angles are,
4×20=80°
5×20=100°
4×20=80°
5×20=100°
I hope this will help you
-by ABHAY
Angles are,
4x, 5x, 4x, 5x
Now,
4x+5x+4x+5x = 360
18x =360
x=360/18
x =20
Now,
Angles are,
4×20=80°
5×20=100°
4×20=80°
5×20=100°
I hope this will help you
-by ABHAY
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