Math, asked by dhasradhansumathi, 1 day ago

Two adjacent angles of a quadrilateral ABCD (having two pairs of parallel opposite sides with adjacent side of unequal length) measure (6x+30)° and (110-2x)°. prove that ABCD is rectangle.​

Answers

Answered by rolipandey308
3

Answer:

(6x+30)°+(110-2x)° = 180 (Co-interior angles property)

6x+30+110-2x = 180

4x+140 = 180

4x = 180-140

4x = 40

x = 10

Now,

6x+30 = 6×10+30

= 90°

110-2x = 110-2×10

= 110-20

= 90°

Since, two angles of the quadrilateral are 90, their adjacent angles will be 90 too. This proves that the quadrilateral is a rectangle.

hope this helps <3

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