Question

two adjacent angles of a rhombus are (3x-4)°and (3x+16) respectively.find the measure of each angles​

Answer 1

Answer:

side of the rhombus =4

=2(3x-4)+(3x+16)=360

=(6x-8)+(6x+32)=360

=12x(-8+32)=360

=12x(24)=360

=12x=360-24

=12x=336

=X=336/12

X=28

(3x-4 )=3×28 -4

84-4

80

(3x+16)=3×28+16

=84+16

=100

please make it brainlist answer

Answer 2

Step-by-step explanation:

let angle A of rhombus be (3x-4)° and angle B be (3x+16)°

we know that

adjacent angle of rhombus is supplementary

so angle A+ angle B=180°

(3x-4) + (3x+16)=180

3x+3x-4+16=180

6x+12=180

6x=180-12

6x= 168

x=168/6

x=28

now

angle A is (3x-4)

put the value of x

3×28-4

80°

angle B is (3x+16)

3×28+16

100°

hence angle A is 80° and angle B is 100°