Two adjacent side of a parallelogram are in the ratio 3:2 the perimeter of the parellogram is 72 cm find the length of each of its sides
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Answered by
19
Hi...☺
Here is your answer...✌
GIVEN THAT,
Two adjacent side of a parallelogram are in the ratio 3:2
Let the common multiple be x
Then Adjacent sides are 3x and 2x
We know that,
Opposite angles of parallelogram are equal
Therefore,
Other two sides are 3x and 2x
Now,
Also given that
Perimeter = 72 cm
Sum of all sides = 72 cm
3x + 2x + 3x + 2x = 72
10x = 72
x = 72/10
x = 7.2 cm
=> 3x = 3×7.2 = 21.6 cm
=> 2x = 2×7.2 = 14.4 cm
HENCE,
Length of sides of given parallelogram are
21.6 cm , 14.4 cm , 21.6 cm , 14 .4 cm
Here is your answer...✌
GIVEN THAT,
Two adjacent side of a parallelogram are in the ratio 3:2
Let the common multiple be x
Then Adjacent sides are 3x and 2x
We know that,
Opposite angles of parallelogram are equal
Therefore,
Other two sides are 3x and 2x
Now,
Also given that
Perimeter = 72 cm
Sum of all sides = 72 cm
3x + 2x + 3x + 2x = 72
10x = 72
x = 72/10
x = 7.2 cm
=> 3x = 3×7.2 = 21.6 cm
=> 2x = 2×7.2 = 14.4 cm
HENCE,
Length of sides of given parallelogram are
21.6 cm , 14.4 cm , 21.6 cm , 14 .4 cm
Answered by
4
Heya ✋
Let see your answer !!!
Let the adjacent sides be 3x and 2x. Then,
Perimeter of a parallelogram = 2(sum of adjacent sides)
=> 72 = 2(3x + 2x)
=> 72/2 = 5x
=> 36 = 5x
=> x = 36/5
=> x = 7.2
Hence , 1st side = 3 × 7.2 = 21.6m
2nd side = 2 × 7.2 = 14.4m
Hence , the adjacent sides of the parallelogram are 21.6m ; 14.4m ; 21.6m and 14.4m.
Thanks:))))
Let see your answer !!!
Let the adjacent sides be 3x and 2x. Then,
Perimeter of a parallelogram = 2(sum of adjacent sides)
=> 72 = 2(3x + 2x)
=> 72/2 = 5x
=> 36 = 5x
=> x = 36/5
=> x = 7.2
Hence , 1st side = 3 × 7.2 = 21.6m
2nd side = 2 × 7.2 = 14.4m
Hence , the adjacent sides of the parallelogram are 21.6m ; 14.4m ; 21.6m and 14.4m.
Thanks:))))
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