Two adjacent side's of a paralellogram are in the ratio 3:8 and its perimeter is 110 cm. Find the sides of the paralellogram.
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Let, ABCD be the parallelogram.
Given :
Two adjacent sides of the parallelogram are in ratio 3:8.
And,
perimeter of the parallelogram is 110cm
AD = 3x cm
DC = 8x cm
AD = BC and DC = AB [ \therefore∴ Opposite sides of parallelogram are equal ]
So,
Perimeter of the parallelogram
=> AB + BC + DC + AD = 110
=> 8x + 3x + 8x + 3x = 110
=> 22x = 110
= X = 110/22
= X = 5
So,
AB = 8x = 8*5 = 40 cm
BC = 3x = 3*5 = 15 cm
DC = 8x = 8*5 = 40 cm
AD = 3x = 3*5 = 15 cm
Answered by
5
Let, ABCD be the parallelogram.
Given :
Two adjacent sides of the parallelogram are in ratio 3:8.
And,
perimeter of the parallelogram is 110cm
AD = 3x cm
DC = 8x cm
AD = BC and DC = AB [ \therefore∴ Opposite sides of parallelogram are equal ]
So,
Perimeter of the parallelogram
=> AB + BC + DC + AD = 110
=> 8x + 3x + 8x + 3x = 110
=> 22x = 110
= X = 110/22
= X = 5
So,
AB = 8x = 8*5 = 40 cm
BC = 3x = 3*5 = 15 cm
DC = 8x = 8*5 = 40 cm
AD = 3x = 3*5 = 15 cm
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