Question

Two adjacent sides of a parallelogram are 10 cm and 12 CM if one diagonal of it is 16 cm long find area of the parallelogram also find the distance between it shorter sides

Answer 1

ABCD is a parallelogram and diagonal divide it into two equal parts
Area of tri. ABC =area of tri. ADC

In triangle ABC

s = a + b + c÷2 = 10+12+16÷2. =19
by heron's formula
$\sqrt{s(s - a)(s - b)(s - c}$

area of triangle ABC = 59.92
Area of parallelogram ABCD = area of tri.(ABC + ADC)
= 59.92+ 59.92
= 119.84