Question

two adjacent sides of a parallelogram are 16 cm and 24 long. the height from the longer side is 15 centimetre. what is the height from the lower side ?​

Answer 1

Solution:-

Given : Two adjacent sides of the parallelogram are AB = 24 cm and BC = 18 cm and the distance between the longer side, DE = 12 cm.

To find : The distance between the shorter side.

Let the distance between the shorter side, DF be 'x' cm.

Area of the parallelogram = Base × Height  

Area of the parallelogram, considering AB as the base = AB × DE

= 24 × 12

Area = 288 cm²

Now considering BC as the base, the area of the parallelogram = BC × DF

= 18 × x

Area = 18x

Since the area of the parallelogram will be the same, if we consider Ab as the base or BC as the base.

So, AB × DE = BC × DF

⇒ 288 18x

x = 288/18

x = 16 cm

So, the distance between the shorter side is 16 cm.

Answer.

Answer 2

Answer:

the distance between the shorter side is 10 cm.

Step-by-step explanation:

Solution:-

Given : Two adjacent sides of the parallelogram are AB = 16 cm and BC = 24cm and the distance between the longer side, DE = 15 cm.

To find : The distance between the shorter side.

Let the distance between the shorter side, DF be 'x' cm.

Area of the parallelogram = Base × Height 

Area of the parallelogram, considering AB as the base = 16× 15

= 16 × 15

Area = 240 cm²

Now considering BC as the base, the area of the parallelogram = BC × DF

= 24 × x

Area = 24x

Since the area of the parallelogram will be the same, if we consider Ab as the base or BC as the base.

So, AB × DE = BC × DF

⇒ 240/ 24x

x = 240/24

x = 10 cm

So, the distance between the shorter side is 10 cm.

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