Question

Two adjacent sides of a parallelogram are 24 cm and 18 cm. If the distance
between longer sides is 12 cm. Find the distance between shorter sides. (3)
/F
In the adjoining fig., ABCD is a rectangle.
(4)
IF Z CEB / ECB - 3:2, find​

Answer 1

Step-by-step explanation:

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Answer 2

Let take 24 cm as the base of parallelogram, then its height is 12 cm.

We know that,

Area of parallelogram = base × height

= 24 × 12 = 288 cm2

Let’s consider d cm to be the distance between the shortest sides.

∴ Area of parallelogram = (18 × d) cm2

18 × d = 288

⇒ d = 288/18 = 16 cm

Therefore, the distance between the shorter sides is 16 cm.

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