Question

Two adjacent sides of a parallelogram are 34cm and 20cm. One of its diagonals is 42cm. Then the area of the parallelogram is

Answer 1

Solution :

Let ΔABC where ,

AB = 34 cm

BC = 20 cm

CA = 42 cm

Find "S"

S = ( a + b + c)/2

⇒ ( 34 + 20 + 42)\2

⇒ 96/2

⇒ 48 cm

By Using  heron's formula

In Δ ABC

⇒ $\sqrt{s ( s-a) ( s- b) ( s-c) }$

⇒ $\sqrt{ 48*14*28*6}$

⇒ 336 cm^2

Finding area of the parallelogram

⇒ 2 * 336

⇒ 672 cm^2

Two adjacent sides of a parallelogram are 34 cm and 20cm. One of its diagonals is 42cm. Then the area of the parallelogram is 672 cm^2