two adjacent sides of a parallelogram are 5cm and 3.5cm one of its diagonals is 6.5cm find the area of parallelogram
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ABCD is 11gm
=>AB = CD = 17cm
(Opposite sides of 11gm are equal)
=>AD = BC = 13cm
Area of ΔABC = Area of ΔACD
Use herons formula :-
Let :-
=>a = 17 cm
=>b = 13 cm
=>c = 20 cm
=>S=a+b+c/2
=>S=17cm+13cm+20cm/2
=>S=50/2
=>S=25 cm
: There ar(ABCD)
=√s(s-a)(s-b)(s-c)
=√25(25-17)(25-13)(25-20)
=√25×8×12×5
=>ar(ABCD)=Area of ΔABC+Area of ΔACD
=2×Ar(ΔABC)
=40×5.5cm²
=220cm²
®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®
Regards :)
Yash Raj ✌
®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®
ABCD is 11gm
=>AB = CD = 17cm
(Opposite sides of 11gm are equal)
=>AD = BC = 13cm
Area of ΔABC = Area of ΔACD
Use herons formula :-
Let :-
=>a = 17 cm
=>b = 13 cm
=>c = 20 cm
=>S=a+b+c/2
=>S=17cm+13cm+20cm/2
=>S=50/2
=>S=25 cm
: There ar(ABCD)
=√s(s-a)(s-b)(s-c)
=√25(25-17)(25-13)(25-20)
=√25×8×12×5
=>ar(ABCD)=Area of ΔABC+Area of ΔACD
=2×Ar(ΔABC)
=40×5.5cm²
=220cm²
®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®
Regards :)
Yash Raj ✌
Attachments:
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