Question

two adjacent sides of a parallelogram are in the ratio 3:8 and its perimeter is 110 cm. find the sides of parallelogram​

Answer 1

Answer:

Let, ABCD be the parallelogram.

Given : Two adjacent sides of the parallelogram are in ratio 3:8.

And,

perimeter of the parallelogram is 110cm

AD = 3x cm

DC = 8x cm

AD = BC and DC = AB [ \therefore∴ Opposite sides of parallelogram are equal ]

So,

Perimeter of the parallelogram

=> AB + BC + DC + AD = 110 cm

=> 8x + 3x + 8x + 3x = 110

=> 22x = 110

=> x = \frac{110}{22}

22

110

=> x = 5

So,

AB = 8x = 8*5 = 40 cm

BC = 3x = 3*5 = 15 cm

DC = 8x = 8*5 = 40 cm

AD = 3x = 3*5 = 15 cm