Two adjacent sides of a parallelogram are in the ratio 3:8 and its perimeter is 110 cm.find the sides of the parallelogram.
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let the side be 3x and its adjacent side be a 8x.then 3X+8X+3X+8X=110
22X=110
X=5.
8X=8*5=40
3X=3*5=15...
22X=110
X=5.
8X=8*5=40
3X=3*5=15...
vaibhavthenua24:
Thanks bhan ji
Answered by
7
ratio of two adjacent sides = 3 : 8
let the constant ratio be 'x'
let the adjacent sides are 3x. , 8x
perimeter = 110cm
2( sum of adjacent sides) = 110cm
2( 3x + 8x) = 110
22x = 110 => x = 5
thus ,
adjacent sides are 3x = 3× 5 = 15cm
and 8x = 8 × 5 = 40cm
since we know opposite sides of parallelogram are equal.
so then , other two sides of parallelogram are
15cm, 40cm
therefore,
All the sides of parallelogram are
15cm, 40cm , 15cm , 40cm
let the constant ratio be 'x'
let the adjacent sides are 3x. , 8x
perimeter = 110cm
2( sum of adjacent sides) = 110cm
2( 3x + 8x) = 110
22x = 110 => x = 5
thus ,
adjacent sides are 3x = 3× 5 = 15cm
and 8x = 8 × 5 = 40cm
since we know opposite sides of parallelogram are equal.
so then , other two sides of parallelogram are
15cm, 40cm
therefore,
All the sides of parallelogram are
15cm, 40cm , 15cm , 40cm
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