Math, asked by amansingh209542, 1 year ago

two adjacent sides of a parallelogram are in the ratio 3:8 and its perimeter is 110 cm find the sides of parallelogram

Answers

Answered by avinashkr19
9
let first side (a) be 3x and second side (b) be 8x
we know that perimeter of parallelogram = 2(a+b)
then 2( 3x + 8x )= 110
= 2×11x= 110
= 11x = 110÷2
11x= 55
x= 55÷11
x=5

then 1st side= 3x=3×5 =15
2nd side= 8x=8×5=40

amansingh209542: correct
amansingh209542: Bro....
avinashkr19: thanks
Answered by Anonymous
5

\bf{\underline{\underline \blue{Solution:-}}}

\sf\underline{\red{\:\:\: AnswEr:-\:\:\:}}

  • All the sides of parallelogram = 15cm, 40cm, 15cm, 40cm

\sf\underline{\red{\:\:\: Given:-\:\:\:}}

  • Two adjacent sides of a parallelogram are in the ratio 3:8 and its perimeter is 110 cm.

\sf\underline{\red{\:\:\: Need\:To\: Find:-\:\:\:}}

  • All the sides of parallelogram = ?

\bf{\underline{\underline \blue{Explanation:-}}}

\sf\underline{\pink{\:\:\: Diagram:-\:\:\:}}

\setlength{ \unitlength}{20} \begin{picture}(3,5) \put(2,2){ \line(1,0){4}}\put(2,2){ \line(1,1){3}}\put(6,2){ \line(1,1){3}}   \put(5,5){ \line(1,0){4}}  \put(2,1.5 ){$ \tt A$ } \put(6, 1.5){$ \tt B $ } \put(5,5.2){$ \tt D $ } \put(9.3, 5){$ \tt C$ } \put(4, 1.5){$ \tt 8x $ } \put(7.5,3 ){$ \tt 3x $ } \put(3, 3.5){$ \tt 3x $ } \put(7,5.2 ){$ \tt 8x $ } \\ \put(8,1)}}\end{picture}

\rule{200}{2}

 \textbf {Let the constant ratio = x}

 \textbf {Let the first adjacent side be 3x}

 \textbf {And Second adjacent side be 8x}

  • Perimeter = 110 Cm [Given]

\dashrightarrow \sf {2( sum\: of \:adjacent \:sides) = 110\:Cm} \\\\

\dashrightarrow \sf {2( 3x + 8x) = 110} \\\\

\dashrightarrow \sf {2 (11x) = 110} \\\\

\dashrightarrow \sf {22x = 110} \\\\

\dashrightarrow \sf {x = \dfrac{\cancel{110}}{\cancel{22}} } \\\\

\dashrightarrow \sf { x = 5 } \\\\

\sf\underline{\green{\:\:\: ThereFore:-\:\:\:}}

First Adjacent side = 3x

First Adjacent side = 3 × 5

First Adjacent side = 15cm

\sf\underline{\green{\:\:\: And:-\:\:\:}}

Second Adjacent side = 8x

Second Adjacent side = 8 × 5

Second Adjacent side = 40cm

\sf\underline{\red{\:\:\: Since:-\:\:\:}}

  • We know opposite sides of parallelogram are equal.

\sf\underline{\red{\:\:\: Then:-\:\:\:}}

  • Other two sides of parallelogram are 15cm and 40cm.

\sf\underline{\red{\:\:\: Thus:-\:\:\:}}

  • All the sides of parallelogram are 15cm, 40cm, 15cm, 40cm.

\rule{200}{2}

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