two adjacent sides of a parallelogram are in the ratio 3:8 and its perimeter is 110 cm find the sides of parallelogram
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let first side (a) be 3x and second side (b) be 8x
we know that perimeter of parallelogram = 2(a+b)
then 2( 3x + 8x )= 110
= 2×11x= 110
= 11x = 110÷2
11x= 55
x= 55÷11
x=5
then 1st side= 3x=3×5 =15
2nd side= 8x=8×5=40
we know that perimeter of parallelogram = 2(a+b)
then 2( 3x + 8x )= 110
= 2×11x= 110
= 11x = 110÷2
11x= 55
x= 55÷11
x=5
then 1st side= 3x=3×5 =15
2nd side= 8x=8×5=40
amansingh209542:
correct
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5
- All the sides of parallelogram = 15cm, 40cm, 15cm, 40cm
- Two adjacent sides of a parallelogram are in the ratio 3:8 and its perimeter is 110 cm.
- All the sides of parallelogram = ?
- Perimeter = 110 Cm [Given]
First Adjacent side = 3x
First Adjacent side = 3 × 5
First Adjacent side = 15cm
Second Adjacent side = 8x
Second Adjacent side = 8 × 5
Second Adjacent side = 40cm
- We know opposite sides of parallelogram are equal.
- Other two sides of parallelogram are 15cm and 40cm.
- All the sides of parallelogram are 15cm, 40cm, 15cm, 40cm.
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