Math, asked by sakshamKumar2320, 5 months ago

Two adjacent sides of a parallelogram are in the ratio 3 is to 8 and its perimeter is 110 CM . find the sides of the parallelogram . Please explain​

Answers

Answered by pooja1784
8

Answer:

given that: adjacent sides are in ratio 3:8

let length =3x and breath =8x

110 = perimeter

110 = 2(3x +8x)

110 = 2(11x)

110 = 22x

110/22 =X

X = 5

so the sides are

3*x = 3*5 = 15

8*x = 8*5 = 40

Answered by kavikhamkar07
2

Answer:

side 1=15 CM, side 2=40cm,side3=15cm ,side4=40cm

Step-by-step explanation:

let the adjacent sides of parallelogram be Side 1 and side 2

therefore,

side 1/side2=3/8

let common multiple be X

side1=3x, Side 2=8x

perimeter of parallelogram =2(l+b)

=2(3x+8x)

=2(11x)

110=22x

x=110/22

x=5

therefore, side 1 =3x=3×5=15

side2=8x=8×5=40

opposite sides of parallelogram are equal

side1=side2=15cm

side 3=side4=40cm

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