Question

two adjacent sides of a parllelogram are 51cm and 37cm one of its diagonals is 20
cm then the area is

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Answer 1

Step-by-step explanation:

Given,

let parallelogram be abcd

ab=51

bc=37

ac=20

s=perimeter of triangle abc

s=(51+37+20)/2

s=53.5cm

area of parallelogram = 2{s√((s-a)(s-b)(s-c))}

= 2{53.5√((53.5-51)(53.5-37)(53.5-20))}

= 2{107√((2.5)(16.5)(33.5))}

=214√(1381.875)

= 214×37.2

=7961cm^2