Question

Two adjacent sides of a rectangle are 15p2- 4q^2
and p² - 12pq. Find the perimeter of rectangle.​

Answer 1

Step-by-step explanation:

Two adjacent sides of a rectangle are 15p²- 4q²

and p² - 12pq are given.

Let length=15p²- 4q²

breadth=p² - 12pq

perimeter of a rectangle =2(l+b)

=2(15p²-4q²+p²-12pq)

Arrange into standard form.

=2(15p²+p²-4q²-12pq)

=2(16p²-4q²-12pq)

=32p²-8q²-24pq

perimeter of a rectangle is 32p²-8q²-24pq.

Hope this will help you .

Answer 2

Step-by-step explanation:

Step-by-step explanation:

Two adjacent sides of a rectangle are 15p²- 4q²

and p² - 12pq are given.

Let length=15p²- 4q²

breadth=p² - 12pq

perimeter of a rectangle =2(l+b)

=2(15p²-4q²+p²-12pq)

Arrange into standard form.

=2(15p²+p²-4q²-12pq)

=2(16p²-4q²-12pq)

=32p²-8q²-24pq

perimeter of a rectangle is 32p²-8q²-24pq.

Hope this will help you .