Question

two adjacent sides of a rectangle are 3 square 2 -5y square 2 and 7x square 2 -xy. finds its permiter

Answer 1

Perimeter of a triangle is 2(l+b)

So, perimeter = 2 ( 3^2-5y^2 + 7x^2 - xy )

= 2( 9 -25y^2 + 49x^2 - xy )

= 18 - 50y^2 + 98x^2 - xy

Hope it helps!

Please correct me if I am wrong!