Question

Two adjacent sides of a rectangle are 3x^2-2y^2 and x^2+3xy. Find its perimeter.

Answer 1

Answer:

$8x^2 - 4y^2 + 6xy$

Step-by-step explanation:

Perimeter of a rectangle = 2×(L+B)

                                        = 2×( $(3x^2 - 2y^2)$ + $(x^2 + 3xy )$ )

                                        = 2× ( $3x^2 - 2y^2+x^2 + 3xy$ )

                                         =2× $4x^2 - 2y^2 + 3xy$

                                         = $8x^2 - 4y^2 + 6xy$