two adjacent sides of a rectangle are 3x^{2} -2y^{2} and x^{2} +3xy. find its perimeter
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in a rectangle adjacent sides means length and breadth ;
Let the length = 3x^2- 2y^2
Breadth= x^2+3xy
PERIMETER OF rectangle =2(l+b)
=2(3x^2-2y^2 + x^2+3xy)
=2(4x^2-2y^2+3xy)
=8x^2-4y^2+6xy
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Answer:
perimeter of rectangle=2X(L+B)
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