Question

two adjacent sides of a rectangle are 5x^2-3y^2 and x^2-2xy find its perimeter

Answer 1

Step-by-step explanation:

Given adjacent sides of a rectangle are 5x

2

−3y

2

and x

2

+2xy

we know that the perimeter of a rectangle with adjacent sides a and b is 2×(a+b)

Perimeter=2((5x

2

−3y

2

)+(x

2

+2xy))

=2(6x

2

−3y

2

+2xy)

=12x

2

−6y

2

+4xy

∴Perimeter=12x

2

−6y

2

+4xy