Question

two adjacent sides of a rectangle are 5x"
20. The perimeter of a triangle is 6p'-4p +9 and two of its sides are P
3p2-5p+3. Find the third side of the triangle.​

Answer 1

Answer:

Given perimeter of triangle is 6p

2

−4p+9 and two of its sides are p

2

−2p+1 and 3p

2

−5p+3.

Let thee third side be c.

we k.n.t perimeter of a triangle p with sides a,b,c is p=a+b+c.

p= 6p

2

−4p+9

a= p

2

−2p+1

b= 3p

2

−5p+3.

p=a+b+c

c=p−a−b

c=(6p

2

−4p+9)-(p

2

−2p+1)-(3p

2

−5p+3)

c=(6−1−3)p

2

+(−4+2+5)p+(9−1−3)

∴c=2p

2

+3p+5

∴ third side of given triangle is 2p

2

+3p+5.