Two adjacent sides of a triangle are 5x-3yand
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ur que is
The two adjacent sides of a rectangle are 5x^2 - 3y^2 and x^2+2xy.find the perimeter
Step-by-step explanation:
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Perimeter = 2 (L + B)
=2×(5x^2 - 3y^2 + x^2 + 2xy)
=2×(5x^2 + x^2 - 3y^2 + 2xy)
=2×(6x^2 - 3y^2 + 2xy)
=12x^2 - 6y^2 + 4xy
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Answer:
Step-by-step explanation:
Length is 5x-3y
Breadth is x-2y
So area we know that Length* Breadth
So, 5x-3y* x-2y
=-1 • (3xy - 5x + 2y) unit^2
is the area
Perimeter we know that
2*(L+B)
=2*(5x-3y+x-2y)
=2*(6x-5y)
12x-10y units is the Perimeter.
Remember
Area of Rectangle = Length*Breadth
Peimeter of Rectangle is 2*(L+B)
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