Question

Two adjacent sides of rectangle are 2a²-4b and 5a²+3b find its perimeter?​

Answer 1

Answer: 14a² - 2b

Step-by-step explanation:

perimeter of a rectangle = 2(sum of its two adjacent sides)

                                       = 2(2a² - 4b + 5a² + 3b)

                                       = 2(7a² - b)

                                       = 14a² - 2b

HOPE THIS HELPS.....

Answer 2

Step-by-step explanation:

Answer:-

The given two sides are :-

$1. \: \: 2 {a}^{2} - 4b$

$2. \: \: 5 {a}^{2} + 3b$

But, what is Perimeter?

The collection of all the sides of a given shape is called perimeter. The boundary measurement .

Perimeter of Rectangle:-

$2(L+B)$

• Where L is length
• Where B is breadth.

Let's Solve!

We simply need to add the sides, that's all.

$\sf{2(2 {a}^{2} - 4b + 5 {a}^{2} + 3b)}$

$\sf{= 2(7 {a}^{2} - b)}$

$\boxed{\bf{14a^2 - 2b}}$

is the required Perimeter.

Remember that:-

• The coefficients of same bases will get added.
• Example a² will get added to a² and not a.
• Sign Conventions are to be noted.