Question

Two aeroplanes start flying from an airport in opposite directions one averaging at a speed of 40 kilometre per hour more than that of the Other if they are 5600 km apart after 5 hours, find their average speeds​ ​

Answer 1

Answer:

ANSWER

Let the speed of one plane be xkmphr

Then the speed of other plane is x+40kmphr

Distance travelled by first plane in 5hrs=speed×time=x×5=5x

Distance travelled by second plane in 5hrs=(x+40)×5

Distance traveled by first plane+Distance traveled by other plane=3400km

⇒5x+5(x+40)=3400

⇒5x+5x+200=3400

⇒10x=3400−200=3200

⇒x=

10

3200

=320kmphr

Speed of first plane=xkmphr=320kmphr

Speed of second plane=x+40=320+40=360kmphr

Step-by-step explanation:

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Answer 2

Answer :-

• Speed of first plane ⇒ 540kmphr
• Speed of second plane ⇒ 580 kmphr

Given :-

➤ Two aeroplanes start flying from an airport in opposite directions one averaging at a speed of 40 kilometre per hour more than that of the Other if they are 5600 km apart after 5 hours .

To find :-

• What is their average speeds ?

Solution :-

➤ Let the speed of one plane be x kmphr

➤ Then the speed of other plane is x + 40kmphr

➤ Distance travelled by first plane in 5hrs.

⇒ speed × time ⇒ x × 5 = 5x

➤ Distance travelled by second plane in 5hrs

⇒ (x + 40) × 5

Now ,

Distance traveled by first plane +Distance traveled by other plane = 5600km

⇒ 5x + 5 (x + 40) ↠ 5600

⇒ 5x + 5x + 200 ↠ 5600

⇒ 10x ↠ 5600 − 200

⇒ 10x ↠ 5400

⇒ x ↠ 5400/10

⇒ x ↠ 540 kmphr

Now ,

put the value of x $.$

➤Speed of first plane ⇒ x kmphr

⇒ 540 kmphr

➤Speed of second plane ⇒ x+40

⇒ 540 + 40

⇒ 580 kmphr

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