Math, asked by ItzKyoFelle, 4 days ago

Two alarm clocks ring their alarms at regular intervals of 50 seconds and 48 seconds. If

they first beep together at 12 noon, at what time will they beep again for the first time?

(a) 12.20 pm
(b) 12.12 pm
(c) 12.11 pm
(d) 12.10 pm
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Answers

Answered by sruthiusha2203
3

Answer:

b)12.12 pm is the correct answer

Step-by-step explanation:

hope it helps you (^3^♪

Answered by aftabahemad
2

In context to question asked,

We have to determine that at what time the both alarm clocks will beep again.

As per question,

Two alarm clocks ring their alarms at regular intervals of 50 seconds and 48 seconds.

As it rang at 12 noon for first time.

So, for determining the time at which both bell rang together, we will determine the LCM of given time interval.

So, LCM of 50 and 48 will be,

50=2 \times 5 \times 5\\48 = 2\times 2 \times 2 \times 2 \times 3\\=>LCM = 2\times 5 \times 5\times 2 \times 2 \times 2 \times 3 = 1200

Hence, both bells will rang together after 1200 seconds.

So, converting 1200 seconds in minutes

We will get,

\frac{1200}{60} = \frac{120}{6} = 20\:minutes

Hence, both bells will rang together at 12:00P.M. + 20\:minutes = 12:20:P.M.

Hence, option a will be correct.

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