Question

two alkanes A and B have 4 and 6 carbon atoms respectively in their molecule. In which physical state will they occur at room temprature​

Answer 1

The physical state of A and B is:

A—gaseous state

B—liquid state.

Answer 2

Alkane A will occur in gaseous state at room temperature and alkane B will occur in liquid state at room temperature.  

Explanation:

• General chemical formula of an alkane is $C_{n}H_{2n+2}$. When there are 4 carbon atoms present in an alkane then its chemical formula will be $C_{4}H_{10}$.

• Hence, $C_{4}H_{10}$ is butane. And, when there are 6 carbon atoms present in an alkane then its chemical formula is $C_{6}H_{14}$. Therefore, $C_{6}H_{14}$ is hexane.

• At room temperature, butane exists as a gas and its boiling point is $-1^{o}C$. Whereas hexane exists as a liquid at room temperature as its boiling point is between $50^{o}C to 70^{o}C$.

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