TWO ALMIRAH ARE PURCHASED FOR 7800 , 200 WAS SPENT ON THE TRANSPORTATION ONE OF THEM IS SOLD AT THE PROFIT OF 40% AND THE OTHER ONE AT A LOSS OF 40% . IF SP WAS SAME IN BOTH THE CASES , FIND THE CP OF EACH ALMIRAH (FIRST ONE TO ANSWER WILL BE MARKED AS BRAINLIEST PLSS ANSWER FAST WITH THE WHOLE SOLUTION)
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Let the selling price of each almirah be x then let the two Almirah be A and B.
A is sold at a profit and B is sold at a loss.
A:
Selling price = x
Buying price = 0.6x
B:
Selling price = x
Buying price = 1.40x
The buying price of the two is 7800 meaning :
0.6x + 1.4x = 7800
2x = 7800
x = 3900
Buying price of A is :
0.6 × 3900 = 2340
B :
1.4 × 3900 = 5460
Since this is inclusive of transportation cost, we subtract 100 from each to get.
A = 2340 - 100 = 2240
B = 5460 - 100 = 5360
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