two almirah are purchased for 7800 rupees .200 rupees was spent on the transportaion .one of them is sold at a profit of 40%and the pther at a loss of 40% .if the selling price was same in both the cases .find the cost price of almirah
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Let the selling price of each almirah be x then let the two Almirah be A and B.
A is sold at a profit and B is sold at a loss.
A:
Selling price = x
Buying price = 0.6x
B:
Selling price = x
Buying price = 1.40x
The buying price of the two is 7800 meaning :
0.6x + 1.4x = 7800
2x = 7800
x = 3900
Buying price of A is :
0.6 × 3900 = 2340
B :
1.4 × 3900 = 5460
Since this is inclusive of transportation cost, we subtract 100 from each to get.
A = 2340 - 100 = 2240
B = 5460 - 100 = 5360
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