Question

two aluminium wires have their lengths in ratio 2:3 and radii in the ratio 1:3 these are connected in parallel across a battery of emf e and of negligible internal resistance find the ratio of their drift velocities of the electrons in the two wires​

Answer 1

Answer:

HeY dude since drift velocity varies inversely w.r.t. to length

Answer 2

The ratio of the drift velocities of the electron in two wires = 3/2

• Drift velocity = I/neA

• I = emf/ resistance

• Resistance of wire = ρl/A

• Then according to the question,

Vd1  =   Emf / (ρl1neA1 /A1)  

and,

Vd2  =   Emf / (ρl2neA2 /A2)

• On dividing the two equations we get ,

Vd1 / Vd2 = l2 / l1

Vd1 / Vd2 = 3/2