Question

Two aluminium wires have their lengths in ratio 2:3 and radii in ratio 1:3 these are connected in parallel accross a battery of emf e and of negligible internal resistance find the ratios of drift velocities of electrons in two wires?

Answer 1

Answer:

ratio of drift speed in two wires is given as 3 : 2

Explanation:

As we know that the resistance of two wires is given as

$R = \rho \frac{L}{A}$

now we know that current in the wire is given as

$i = neA v_d$

so we have

$v_d = \frac{i}{ne A}$

now we can write

$i = \frac{V}{R}$

so we have

$v_d = \frac{V}{\frac{\rho L}{A} neA}$

so we have

$v_d = \frac{V}{\rho L ne}$

now the ratio of drift speed in two wires inversely depends on the length of the wire

so we will have

$\frac{v_d_1}{v_d_2} = \frac{L_2}{L_1}$

so we have

$\frac{v_d_1}{v_d_2} = \frac{3}{2}$

#Learn

Topic : Drift speed

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