Two aluminum conductor have equal length The cross sectional area of one conductor is four times that of the other If the conductor having a smaller cross sectional area has resistance of 100 ohm the resistance of other conductor will be
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Answer:
25 ohm
Explanation:
resistance = resistivity × length / area of cross section
let the length equal to l
the smaller area equal to a
so the larger area equal to 4a
resistivity equal to t
resistance of smaller area equal to r = 100 ohm
resistance of larger area equal to R
so
resistance = resistivity × length / area of cross section
r = t l / a
and
R = t l / 4a
= 1/4 ( t l / a )
= 1/4 ( r )
= 1/4 (100)
R = 25 ohm.
hope it helped.
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