two angels of a polygon are right angels and the remaining are 120 degree each.find the number of sides in it
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Two angles of a polygon are right angles and the remaining angles are 120∘each. Find the number of sides in it.
This question is based on the sum of the internal angles of a polygon. First of all, we assume that the number of sides is n. Now by using the formula of the sum of internal angles of a polygon –
Sum of internal angles of nsided polygon =(n−2)×180∘
By given angles in the question, we make an equation in n and solve it and get the number of sides of a polygon.
Complete step by step answer:
Let us start by understanding what a polygon is. A polygon is a plane figure that is described by a finite number of straight-line segments called edges. There are an equal number of edges and angles in a polygon, and the sum of interior angles and side’s relation is –
S=(n−2)π radian
S=(n−2)×180∘ degree
Let us assume that there are n sides in a polygon. Thus, there are also n internal angles in the polygon.
According to the question, we have the data as below.
Out ofn, two angles are right angle. And the remaining (n−2) angles are 120∘each.
So, we can write that
Sum of internal angles of polygon =(2×90∘)+(n−2)120∘ …(1)
As we know that sum of interior angles of n sided polygon
=(n−2)×180∘ …(2)
Now, by equation (1) and (2), we can equate them as
(n−2)×180∘=(2×90∘)+(n−2)120∘
On dividing by 60∘on both sides, we get
⇒(n−2)×180∘60=(2×90∘)60+(n−2)120∘60
⇒3(n−2)=3+2(n−2)
By subtracting 2(n−2) on both sides, we get
⇒3(n−2)−2(n−2)=3+2(n−2)−2(n−2)
⇒(n−2)=3
By adding 2 on both sides, we get
⇒n−2+2=3+2
⇒n=5
Hence, the number of sides in the polygon is 5.
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Answer:
5
Step-by-step explanation:
Let number of sides of polygon is n.
Two angles of a polygon are right angles and the remaining are 120
o
each
Sum of total angles of a polygon is = 180
o
(n−2)
n= number of sides of polygon
Now,
2×90+n-2×120=180(n-2)
180degree n - 120 degree n = 180+360-240
60n = 300
n=5
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