Question

Two Angles are complementary. The larger angle is 3° less than twice the measure of smaller angle. find the measure of each angle.

Answer 1

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Let the smaller angle is x °
Larger angle is 2x - 3°
As the angles are complementary hence their sum is 90°

ATQ
$x + (2x - 3) = 90 \\ x + 2x - 3 = 90 \\ 3x = 90 + 3 \\ 3x = 93 \\ x = \frac{93}{3} \\ x = 31 \\ so \: larger \: angle \: is \\ 2 \times 31 - 3 \\ = 62 - 3 \\ = 59$
Smaller angle is 31°

Larger angle is 59°

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Answer 2

Answer:

\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!!!}}}

Hey Mate!!!!

< b ><b>

Let the smaller angle is x °

Larger angle is 2x - 3°

As the angles are complementary hence their sum is 90°

ATQ

\begin{gathered}x + (2x - 3) = 90 \\ x + 2x - 3 = 90 \\ 3x = 90 + 3 \\ 3x = 93 \\ x = \frac{93}{3} \\ x = 31 \\ so \: larger \: angle \: is \\ 2 \times 31 - 3 \\ = 62 - 3 \\ = 59\end{gathered}

x+(2x−3)=90

x+2x−3=90

3x=90+3

3x=93

x=

3

93

x=31

solargerangleis

2×31−3

=62−3

=59

Smaller angle is 31°

Larger angle is 59°

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