two angles are in the ratio of 7: 8 are supplementary to each other, then find the angles
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SOLUTION
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let the both angle be 7x and 8 x respectively.
A/q
7x+8x=180°
=>15x=180°
=>x=180°/15
=>x=12°
then 1 st angle =12*7=84°
and, second angle =12*8=96°
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let common multiple be x
7x+8x=180
x=180÷15
=12
1st angle=7x=7×12 = 63 degree
2nd angle=8x=8×12 =96
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