Two angles are supplementary if one of them is 30°. less than 5 time the other find the angles...
Answers
Answered by
10
Hii there!!!
Let one angle be x
Another angle= 5x-30
Equation formed,
x+5x-30=180°
6x= 180+30
x= 210/6
x= 35° ANS
Another angle= 5*35-30
=175-30= 145° ANS
Hope it helps. ....
Let one angle be x
Another angle= 5x-30
Equation formed,
x+5x-30=180°
6x= 180+30
x= 210/6
x= 35° ANS
Another angle= 5*35-30
=175-30= 145° ANS
Hope it helps. ....
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Answered by
13
Heya !!
Here's your answer !!!
assuming the one angle be "k°"
so, another must be (5×k-30°)
as these angles are supplementary to each other.
then,
K+5k-30° = 180°
6k = 180°+30°
k= 210°/6
k= 35°
so, frist angle be 35°
and second angle be 145
Glad help you,
it helps you,
thanks ☻
@vaibhav246
Here's your answer !!!
assuming the one angle be "k°"
so, another must be (5×k-30°)
as these angles are supplementary to each other.
then,
K+5k-30° = 180°
6k = 180°+30°
k= 210°/6
k= 35°
so, frist angle be 35°
and second angle be 145
Glad help you,
it helps you,
thanks ☻
@vaibhav246
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