Two angles are supplementary. The larger angle is 20o more than thrice the
smaller. Find the angles.
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Let the angles be A and B ,such that B>A ,then , we know that supplementary angles have a sum of 180° ,so,
A+B=180°−−−−−−−−(i)
Now , if we formulate the given question, we get:
B=3A−20° ,so, if we put this value in equation (i), we get:
A+3A−20°=180°⟹4A=200°⟹A=50° ,then,
B=180°−A=180°−50°⟹B=130°
So, the 2 angles are 50° and 130° ,
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