Two angles of a a quadrilateral are 50° and 80° amd other angles are in the ratio of 8:15, fina the value of other tep angles.
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hey..
sum of angles in a quadrilateral = 360°
50° + 80° + 8x + 15x = 360
130° + 23x = 360°
23x = 360° - 130°
23x = 230°
x = 230/23
x = 10°
8x = 8(10) = 80°
15x = 15(10) = 150°
therefore 80° and 150° are the other two angles
sum of angles in a quadrilateral = 360°
50° + 80° + 8x + 15x = 360
130° + 23x = 360°
23x = 360° - 130°
23x = 230°
x = 230/23
x = 10°
8x = 8(10) = 80°
15x = 15(10) = 150°
therefore 80° and 150° are the other two angles
Anonymous:
Good
Answered by
41
Given, two angles of a quadrilateral are 50° and 80°
Given, the other two angles are in the ratio 8 : 15
Let the constant be x
Let the other two angles be 8x and 15x
Sum of all angles of a quadrilateral is 360°
According to the question,
50 + 80 + 8x + 15x = 360
➾ 130 + 23x = 360
➾ 23x = 360 - 130
➾ 23x = 230
➾ x = 10
∴ 1st angle ➾ 8x
➾ 8 × 10
➾ 80°
∴ 2nd angle ➾ 15x
➾ 15 × 10
➾ 150°
Given, the other two angles are in the ratio 8 : 15
Let the constant be x
Let the other two angles be 8x and 15x
Sum of all angles of a quadrilateral is 360°
According to the question,
50 + 80 + 8x + 15x = 360
➾ 130 + 23x = 360
➾ 23x = 360 - 130
➾ 23x = 230
➾ x = 10
∴ 1st angle ➾ 8x
➾ 8 × 10
➾ 80°
∴ 2nd angle ➾ 15x
➾ 15 × 10
➾ 150°
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