Question

Two angles of a
in triangle is
equal and third
angle is greater
than each one of them by
by 118​

Answer 1

Answer:

it is a pythagroas of maths

Answer 2

Answer:

let angle 1 = a

let angle 2 = b

angle a = angle b (given)

let angle 3= (a+ 118)+( b+118)

By angle sum property

a + b + (a+118) + (b+118) =180

2a+ (a+118) + (a + 118) =180

2a + a² +(118)² = 180

3a²+ (118)² = 180

3a² = 180 - (118)²

can't do anymore.......... sorry!