Question

Two angles of a polygon are right angle and the remaining are 160 degree each.Find the numbers of sides that the polygon has?​

Answer 1

Given :-

Two angles of a polygon are right angle.

Remaining angle = 160 degree each

To Find :-

The number of sides of the polygon.

Solution :-

Given that,

Two angles of a polygon are right angle and the remaining are 160 degree each.

Let us consider 'n' to be the number of sides.

Sum of angles = $\sf 2 \times 90^{o} + (n - 2) \times 160^{o}$

Sum = $\sf 180^{o} + 160n - 340$

As we know,

Sum of all angles of a polygon = $\sf 180^{o}(n-2)$

According to the question,

$\sf 180n - 360^{o} = 180^{o} + 160n - 340$

$\sf 180n - 160n = 180 - 340 + 360$

$\sf 20n=-160+360$

$\sf 20n=200$

$\sf n =\dfrac{200}{20}$

$\sf n=10$

Therefore, the polygon has 10 sides.

Answer 2

Answer:

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