Two angles of a quadrilateral are 50° and 70° and other two angles are in the ratio 13:11,then find measures of the remaining two angles.
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Let take the other two angles as 13x and 11x.
As we know that the sum of a quadilateral is 360°.
Therefore, 50°+70°+13x+11x=360°
=》120°+24x=360°
=》24x =360°-120°
=》24x =240°
=》x =240÷24
=》x =10
Now, 13x=13×10=130°
11x =11×10=110°
As we know that the sum of a quadilateral is 360°.
Therefore, 50°+70°+13x+11x=360°
=》120°+24x=360°
=》24x =360°-120°
=》24x =240°
=》x =240÷24
=》x =10
Now, 13x=13×10=130°
11x =11×10=110°
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3
The measure of angle 3 is 130° and that of angle 4 is 110°.
Given: Two angles of a quadrilateral are 50° and 70°
The remaining two angles are in the ratio 13:11
To Find: Measure of the remaining two angles of the quadrilateral
Solution:
We know by the Angle Sum Property,
The Sum of all four angles of a quadrilateral is 360°
Let angle 1 = 50°
Let angle 2 = 70°
Since angle3 : angle4 = 13:11
Let angle 3 = 13x
Let angle 4 = 11x
Angle1 + Angle2 + Angle3 + Angle4 = 360°
50° + 70° + 13x + 11x = 360
24x = 360° - 120°
24x = 240°
x = 10°
By placing the value of x
Angle 3 = 13 x 10
= 130°
Angle 4 = 11 x 10
= 110°
Therefore, the measure of angle 3 is 130° and that of angle 4 is 110°.
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